complete the chart and answer the post calculation questions please

36 At 5 in. 36.42 Average distance (d) = (40.25) + (39.33) + (36.83) + [(36.42)/4) = 38.21 ft. Speedometer reading entering skid (s) = 32 mph NA Drag factor (f ) = 30d (32mph)2 30(38.21 ft) = 0.893 Data Test Skid 1 Test Skid 2 Test Skid 3 Accident Vehicle Right front tire 40 ft 3 in. 39 ft 8 in. 43 ft 6 in. 54 ft 2 in. Left front tire 39 ft 4 in. 40 ft 4 in. 43 ft 4 in. 54 ft 6 in. Right rear tire 36 ft 10 in. 37 ft 6 in. 41 ft 5 in. 51 ft 10 in. Left rear tire 36 ft 5 in. 37 ft 10 in. 41 ft 10 in. 51 ft 4 in. Average d (ft) 38.21 ft Starting speed 32 mph 32 mph 34 mph Drag factor 0.893 flow= Post Calculation Questions: 1. If the posted speed at the accident site was 40 mph, was the car in this exercise speeding when it skid to a stop? 2. Why would the lowest value for drag factor used in the calculation for the accident speed and not the highest or the average of the drag factors