Question: Complete the remove_multiples () function which removes all the elements in the parameter list, number list, which are multiples of the parameter, multiples of. def

 Complete the remove_multiples () function which removes all the elements in

Complete the remove_multiples () function which removes all the elements in the parameter list, number list, which are multiples of the parameter, multiples of. def remove_multiples (number_list, multiples_of): First iteration: index: 0 Simple solution: number_list[0] is 25, to cut the list from the end, -> pop(0) to remove it so the length of the list is no -> current size is 2!!!, [4,10] longer an issue. 2nd iteration: index: 1 number_list[1] -> 10 (not 4) First iteration: index: 2 -> pop(1) to remove it number_list[2] is 10, -> current size = 1, [4] -> pop(2) to remove it, [25,4] Loop: 3 iterations in total 3rd iteration: index: 2 2nd iteration: index: 1 ERROR! Only one element left number_list[1] -> 4 no change def main (): numbers = 25 4, 10] 3rd iteration: index: 0 print (numbers) number_list[O] is 25, remove_multiples (numbers, -> pop(0) to remove it, [4] 5) print("Numbers left", s) number [25, 4, 10] main() Numbers left [4]

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