Complete the table below (i.e. fill in the memory map) to show the state of memory after the following C fragment has been executed. Assume the ATmega128 platform, and all the variables are in the stack (and thus the storage is allocated from high address to low address). Remember the ATmega128 is a little endian architecture (i.e. least significant byte of a variable is stored in the lowest address)

Complete the table below (i.e. fill in the memory map) to show the state of memory after the following C fragment has been executed. Assume the ATmega128 platform, and all the variables are in the stack (and thus the storage is allocated from high address to low address). Remember the ATmega128 is a little endian architecture (i.e. least significant byte of a variable is stored in the lowest address) Be very careful with this question (-5pts for each incorrect value) Address Variable Name Value 0xFFFF OxFFFEcoord ptr. 0xFFFD 0xFFFCnumptr tmade struct sRSEd shaE x; ghax y; shaE *numetx; shaz** shes a 0x07; 0xFFF9 0xFFF8 my coord[11.v 0xFFF7 my coord[1].x int main () seord REE=w.ese?d; | 0xFFF6 oord[0].y coordlO OxFFF5 0xFFF4 coord[0].x 10xFFF3 numarray[1] LOxFFFI num array[0] x33; OxFFF2 y=0x44; = 0x5040