= Composition = 0 wt% C Composition = 0 at% C Temperature = 400 C C Temperature = 752 F 20 25 = Composition (at% C) 10 15 5 1600 1538*9493 C C C L 1400 2500 1394 C 7+ 1200 1147 C 2.14 4.30 12000 Temperature (C) 7, Austenite 1000 912 C Temperature (F) 7 + Fe3C 1500 727 C 800 b+y 0.76 600 0.022 ., Feritte 1085 C a - Fec Cementite (Fe,c) 1000 400 1 2 5 6 6.70 (Fe) 3 4 Composition (wt% C) For some iron-carbon alloy, the mass fractions of total ferrite and total cementite are 0.53 and 0.47, respectively. (a) On the basis of carbon content is this alloy classified as a steel or a cast iron? (b) If the alloy is a steel, is it hypoeutectoid or hypereutectoid? If a cast iron, is it hypoeutectic or hypereutectic? You may find Animated Graph: Figure 10.28 useful