Composition of gas and properties: C (0.875) i-C4 (0.006) n-C5 (0.008) Tpc www.am : 378R Well...
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Composition of gas and properties: C₁ (0.875) i-C4 (0.006) n-C5 (0.008) Tpc www.am : 378°R Well and Reservoir Variables T = 180°F 640°R Pi = 4613 psi Zi 0.945 0.0244 cp 78 ft Mi = h Sw Sg $ C₂ (0.083) n-C4(0.002) n-C6(0.001) = rw Ppc = 671 psi = 0.27 = 0.73 wedbankde C3(0.021) i-C5(0.003) C7+(0.001) k = 0.17 md Yg = 0.65 : 0.14 0.328 ft (7 7/8-in. well) p² - P²wf = 1424 µ2T (1n 0.472 re +s) c q+ a Tw kh 1424ūZT D kh qª (4-32) Assume that a gas well reached stabilized flow as described by Eq. (4-32). With the data in Appendix C and r = 1490 ft, -0.022 cp, Z=0.93, c = 1.5 x 10psi¨¹, D=10³, re and puf 1000 psi, compute the expected flow rate for the given permeability of 0.17 md and for permeabilities 10 and 100 times larger. www.www Composition of gas and properties: C₁ (0.875) i-C4 (0.006) n-C5 (0.008) Tpc www.am : 378°R Well and Reservoir Variables T = 180°F 640°R Pi = 4613 psi Zi 0.945 0.0244 cp 78 ft Mi = h Sw Sg $ C₂ (0.083) n-C4(0.002) n-C6(0.001) = rw Ppc = 671 psi = 0.27 = 0.73 wedbankde C3(0.021) i-C5(0.003) C7+(0.001) k = 0.17 md Yg = 0.65 : 0.14 0.328 ft (7 7/8-in. well) p² - P²wf = 1424µŽT (in 0.472 re +s) c q+ a Tw kh 1424ūZT D kh qª (4-32) Assume that a gas well reached stabilized flow as described by Eq. (4-32). With the data in Appendix Cand r = 1490 ft, -0.022 cp, Z=0.93, c, = 1.5x 10psi¨¹, D=10³, re Ct and puf 1000 psi, compute the expected flow rate for the given permeability of 0.17 md and for permeabilities 10 and 100 times larger. www.www Composition of gas and properties: C₁ (0.875) i-C4 (0.006) n-C5 (0.008) Tpc www.am : 378°R Well and Reservoir Variables T = 180°F 640°R Pi = 4613 psi Zi 0.945 0.0244 cp 78 ft Mi = h Sw Sg $ C₂ (0.083) n-C4(0.002) n-C6(0.001) = rw Ppc = 671 psi = 0.27 = 0.73 wedbankde C3(0.021) i-C5(0.003) C7+(0.001) k = 0.17 md Yg = 0.65 : 0.14 0.328 ft (7 7/8-in. well) p² - P²wf = 1424 µ2T (1n 0.472 re +s) c q+ a Tw kh 1424ūZT D kh qª (4-32) Assume that a gas well reached stabilized flow as described by Eq. (4-32). With the data in Appendix C and r = 1490 ft, -0.022 cp, Z=0.93, c = 1.5 x 10psi¨¹, D=10³, re and puf 1000 psi, compute the expected flow rate for the given permeability of 0.17 md and for permeabilities 10 and 100 times larger. www.www Composition of gas and properties: C₁ (0.875) i-C4 (0.006) n-C5 (0.008) Tpc www.am : 378°R Well and Reservoir Variables T = 180°F 640°R Pi = 4613 psi Zi 0.945 0.0244 cp 78 ft Mi = h Sw Sg $ C₂ (0.083) n-C4(0.002) n-C6(0.001) = rw Ppc = 671 psi = 0.27 = 0.73 wedbankde C3(0.021) i-C5(0.003) C7+(0.001) k = 0.17 md Yg = 0.65 : 0.14 0.328 ft (7 7/8-in. well) p² - P²wf = 1424µŽT (in 0.472 re +s) c q+ a Tw kh 1424ūZT D kh qª (4-32) Assume that a gas well reached stabilized flow as described by Eq. (4-32). With the data in Appendix Cand r = 1490 ft, -0.022 cp, Z=0.93, c, = 1.5x 10psi¨¹, D=10³, re Ct and puf 1000 psi, compute the expected flow rate for the given permeability of 0.17 md and for permeabilities 10 and 100 times larger. www.www
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We must enter the following values into Eq 432 in order to calculate the estimated flow rate 1424 1 0472 1424 1 q kh 1424ZTD 0472r e 1 r w s kh 1424ZT... View the full answer
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