Compute the charge on the capacitor just before the switch is thrown from position $2$ back to position $1.$

q $=.$ C

Part B

Compute the voltage drops across the resistor at the instant described in part A$.$

Vresistor $=.$ V$.$

Part C

Compute the voltage drops across the capacitor at the instant described in part A$.$

Vcapacitor $=.$ V

Part D

Compute the voltage drops across the resistor just after the switch is thrown from position $2$ back to position $1.$

Vresistor $=.$ V

Part E

Compute the voltage drops across the capacitor just after the switch is thrown from position $2$ back to position $1.$

Vcapacitor $=.$ V

Part F

Compute the charge on the capacitor $10\mathrm{.}0$ msms after the switch is thrown from position $2$ back to position $1.$

q$=.$ C Part C

A capacitor with $\backslash ($ C$=1\mathrm{.}70\backslash$times $10^\{-5\}\backslash$mathrm$\{$~F$\}\backslash )$ is connected as shown in the figure $($Figure $1)$ with a resistor with $\backslash ($ R$=970\backslash$Omega $\backslash )$ and an emf source with $\backslash (\backslash$mathcal$\{$E$\}=18\mathrm{.}0\backslash$mathrm$\{$~V$\}\backslash )$ and negligible internal resistance. Initially the capacitor is uncharged and the switch $\backslash ($ S $\backslash )$ is in position $1.$ The switch is then moved to position $2,$ so that the capacitor begins to charge. After the switch has been in position $2$ for $10\mathrm{.}0$ ms $,$ the switch is moved back to position $1$ so that the capacitor begins to discharge.

Figure

Compute the voltage drops across the capacitor at the instant described in part A $.$

Request Answer

Part D

Compute the voltage drops across the resistor just after the switch is thrown from position $2$ back to position $1.$ A capacitor with $\backslash ($ C$=1\mathrm{.}70\backslash$times $10^\{-5\}\backslash$mathrm$\{$~F$\}\backslash )$ is connected as shown in the figure $($Figure $1)$ with a resistor with $\backslash ($ R$=970\backslash$Omega $\backslash )$ and an emf source with $\backslash (\backslash$mathcal$\{$E$\}=18\mathrm{.}0\backslash$mathrm$\{$~V$\}\backslash )$ and negligible internal resistance. Initially the capacitor is uncharged and the switch $\backslash ($ S $\backslash )$ is in position $1.$ The switch is then moved to position $2,$ so that the capacitor begins to charge. After the switch has been in position $2$ for $10\mathrm{.}0$ ms $,$ the switch is moved back to position $1$ so that the capacitor begins to discharge.

Figure

Part A

Compute the charge on the capacitor just before the switch is thrown from position $2$ back to position $1.$

Part B

Compute the voltage drops across the resistor at the instant described in part A $.$