Compute the code that return the matrix M = AT A for a given matrix A- the superscrupt T denoted the transpose. I have started the code for you, which gets the dimension of the matrix, and creates the zero matrix of the correct size. I have also provided some of...e loops involved. # perform and return the multiplication of $A TAS import numpy as np def multiply_At_A (A): # these lines set up the correct dimensions of the returned matrix. # the matrix A is of dimension dim1 x dim2 # the matrix A^T (transpose of A) is dim2 x diml # the matrix (A^T A) is of dimension dim2 x dim2 dim1 =A.shape [0] dim2 = A.shape [1] matrix = np.zeros ([dim2, dim2]) for i in range (dim2) : for j in range (dim2): #complete the final loop to compute matrix[i,j] #your code here return matrix Activate Windows Go to Settings to activate Windows.