Compute the total reactions at A and B on the truss shown (please explain the parts...
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Compute the total reactions at A and B on the truss shown (please explain the parts of the shown solution) EMA = 0 24Rg + 3(20) + 3()(22.4) = 18()(22.4) + 18(30) + 12(20) + 6(10) Rp = 46.27 kN answer 22.4 kN 20 kN 6 m 3 m 3 m A 6 m 6 m 6 m 6 m 10 kN 20 kN 30 KN EMB - 0 244v-3(20) + 3(융)(22.4) + 6(8)(22.4) +6(30) + 12(20) + 18(10) %3D Ay = 33.76 kN EFH - 0 Ag = 20 +(22.4) AH = 30.02 kN VA+ Ay? V30.02 + 33.76 RA RA %3D RA = 45.18 kN Ay Ag tan e Ar 33.76 tan eAz 30.02 tan 0Ar- 48.36" Thus, RA = 45.18 kN up to the right at 48.36° from horizontal. answer Compute the total reactions at A and B on the truss shown (please explain the parts of the shown solution) EMA = 0 24Rg + 3(20) + 3()(22.4) = 18()(22.4) + 18(30) + 12(20) + 6(10) Rp = 46.27 kN answer 22.4 kN 20 kN 6 m 3 m 3 m A 6 m 6 m 6 m 6 m 10 kN 20 kN 30 KN EMB - 0 244v-3(20) + 3(융)(22.4) + 6(8)(22.4) +6(30) + 12(20) + 18(10) %3D Ay = 33.76 kN EFH - 0 Ag = 20 +(22.4) AH = 30.02 kN VA+ Ay? V30.02 + 33.76 RA RA %3D RA = 45.18 kN Ay Ag tan e Ar 33.76 tan eAz 30.02 tan 0Ar- 48.36" Thus, RA = 45.18 kN up to the right at 48.36° from horizontal. answer
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