Question: Computer Network LAN Network Topology Image Use the image as a reference, if the values are A, B, C and D (3rd octet) with the
Computer Network

LAN Network Topology Image
Use the image as a reference, if the values are A, B, C and D (3rd octet) with the following conditions:
- Value A = the number of each digit of your number (the number of each digit is 29)
- Value B = A + 1
- Value C = A + 2
- Value D = A + 3
- x1, y1, z1 are the interfaces for the router gateway, while x2, x3, y2, y3, z2, z3 are for the router interface
a. Find the Routing Table R1, R2, and R3 using the following table!
| Destination | Next hop | Interface |
b. With the Routing Table that you have specified in point a, which path will PC1B take when communicating with PC2B and PC3B
c. In theory there is a routing table for Network Address 0.0.0.0 with a Subnet Mask of 0.0.0.0, explain the function of this routing table?
d. Does the image network require routing at point c? Why?
PC3A 172.16.C.2/24 yl 172.16.C.1/24 SW3 y2 172.16.B.10/30 y3 172.16.B.6/30 R3 PC3B 172.16.C.254/24 PC1B 172.16.A.254/24 x3 172.16.B.9/30 z3 172.16.B.5/30 PC2B SW1 172.16.D.254/24 xl 172.16.A.1/24 x2 172.16.B.1/30 SW2 z2 172.16.B.2/30 R2 z1 172.16.D. 1/24 PC1A R1 172.16.A.2/24 PC2A 172.16.D.2/24 PC3A 172.16.C.2/24 yl 172.16.C.1/24 SW3 y2 172.16.B.10/30 y3 172.16.B.6/30 R3 PC3B 172.16.C.254/24 PC1B 172.16.A.254/24 x3 172.16.B.9/30 z3 172.16.B.5/30 PC2B SW1 172.16.D.254/24 xl 172.16.A.1/24 x2 172.16.B.1/30 SW2 z2 172.16.B.2/30 R2 z1 172.16.D. 1/24 PC1A R1 172.16.A.2/24 PC2A 172.16.D.2/24
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