Computing ANOVA Source of 5S df MS F Variance Between In (M - GM)? 9- 1 SSbetween MSbetween treatments d fbetween MSerror/residual Error/Residual ESS each treatment N- 9 SSerror/residual (within dferrer/residual treatments)Descriptive Statistics Dependent Variable: SleepDuration ExerciseGroup Mean Desifii:in N AM 7.9235 1.07575 55 PM_ _7.3802 1.11881 55 nore | 68809 | 1.,36405 | 35 Total 7.3948 1.19236 165 1. Why is an ANOVA an appropriate test for this study? There are more than two groups and the outcome variable is measured on an ordinal scale. There are more than two groups and the outcome variable is measured on an interval/ratio scale. 2. There are 55 people in each group in this study. What assumption does this most directly influence? a. Homogeneity of variance. b. Independence. c. Normality. . The null hypothesis for the ANOVA is that a. all three means are equal to each other. L2 b. none of the means are equal to each other. I . Compute SSg 5. Compute dfgg 6. MSpe; 7. Compute SS4rror 8. Compute df .rqr 0 . Compute mserror 10. The F value is the ratio of between-treatment to within-treatment variability. What is the F value for this ANOVA? 11. Look up critical value (Table C in the appendix) - Are the results significant? 12. Compute effect size. 13. Write an APA-style summary, using the examples in Activities 8.1 as a guide. Be sure to include tables in your summary