concatenate_dict(dict_list:list)->dict This function will be given a single parameter known as the Dictionary List. Your job is to combine all the dictionaries found in the dictionary list into a single dictionary and return it. There are two rules for adding values to the dictionary: You must add key-value pairs to the dictionary in the same order they are found in the Dictionary List. If the key already exists, it cannot be overwritten. In other words, if two or more dictionaries have the same key, the key to be added cannot be overwritten by the subsequent dictionaries.

Example: Dictionary List: [{'Z': 6, 'k': 10, 'w': 3, 'I': 8, 'Y': 5}, {'Y': 1, 'Z': 4}, {'X': 2, 'L': 5}]

Expected: {'Z': 6, 'k': 10, 'w': 3, 'I': 8, 'Y': 5, 'X': 2, 'L': 5}

Dictionary List: [{'z': 0}, {'z': 7}]

Expected: {'z': 0}

Dictionary List: [{'b': 7}, {'b': 10, 'A': 8, 'Z': 2, 'V': 1}]

Expected: {'b': 7, 'A': 8, 'Z': 2, 'V': 1}

unique_values(a_dict:dict)-> dict This function will receive a single dictionary parameter known as a_dict. a_dict will contain a single letter as a string and numbers as values. This function is supposed to search a_dict to find all values that appear only once in the a_dict. The function will create another dictionary named to_ret. For all values that appear once in a_dict the function will add the value as a key in to_ret and set the value of the key to the key of the value in a_dict (swap the key-value pairs, since a_dict contains letters to numbers, to_ret will contain Numbers to Letters). Finally, the function should return to_ret.

Example: a_dict: {'X': 2, 'Y': 5, 'N': 2, 'L': 2, 'W': 1, 'G': 0, 'R': 1}

Expected: {5: 'Y', 0: 'G'} a_dict: {'Z': 3, 'P': 3, 'E': 2, 'G': 0, 'T': 5, 'L': 1, 'Q': 0} to_ret: {2: 'E', 5: 'T', 1: 'L'} a_dict: {'E': 3, 'X': 3} to_ret: {} a_dict: {'G': 3, 'D': 3, 'C': 4, 'Q': 1, 'H': 1, 'M': 2, 'Z': 1, 'W': 3} to_ret: {4: 'C', 2: 'M'} a_dict: {'O': 2, 'T': 1, 'L': 5, 'W': 5, 'Z': 4, 'M': 5, 'B': 4, 'D': 0, 'F': 3, 'E': 1} to_ret: {2: 'O', 0: 'D', 3: 'F'}

dict_from_string(dict_str:str)->dict This function will be given a single parameter, a string representing a dictionary. Your job is to convert the string into an actual dictionary and return the dictionary. Make sure all key-value pairs in the string exist in the newly created dictionary. The string will contain only numbers or single letters as key values pairs. Make sure all letters are kept as strings and all numbers are converted to integers in the newly created dictionary.

Example: String Input: '{9: 'V', 'G': 0, 'M': 9, 'u': 3, 2: 'o', 8: 'u', 'q': 9, 'D': 1}''

Expected: {9: 'V', 'G': 0, 'M': 9, 'u': 3, 2: 'o', 8: 'u', 'q': 9, 'D': 1}

String Input: '{10: 'D', 1: 'Z', 5: 'a'}'

Expected: {10: 'D', 1: 'Z', 5: 'a'}

String Input: '{'M': 2, 'V': 0, 3: 'x', 6: 'J', 5: 'J', 7: 'T', 8: 'P', 4: 'q', 1: 'h'}'

Expected: {'M': 2, 'V': 0, 3: 'x', 6: 'J', 5: 'J', 7: 'T', 8: 'P', 4: 'q', 1: 'h'} String Input: '{3: 'D', 10: 'T', 7: 'm', 'u': 9, 't': 5, 6: 'Z', 'H': 10, 'B': 6}' Expected: {3: 'D', 10: 'T', 7: 'm', 'u': 9, 't': 5, 6: 'Z', 'H': 10, 'B': 6} String Input: '{'q': 10, 6: 'O', 'm': 6}' Expected: {'q': 10, 6: 'O', 'm': 6} flip_matrix(mat:list)->list You will be given a single parameter a 2D list (A list with lists within it) this will look like a 2D matrix when printed out, see examples below. Your job is to flip the matrix on its horizontal axis. In other words, flip the matrix horizontally so that the bottom is at top and the top is at the bottom. Return the flipped matrix. To print the matrix to the console: print(' '.join([''.join(['{:4}'.format(item) for item in row]) for row in mat])) Example: Matrix: W R I T X H D R L G L K F M V G I S T C W N M N F Expected: W N M N F G I S T C L K F M V H D R L G W R I T X Matrix: L C S P Expected: S P L C Matrix: A D J A Q H J C I Expected: J C I A Q H A D J