Question: confirm that my initial conditions are correct : dx/dt = x^2, dx/dt = -xy and du/dt = u^2. Initial conditions are that u = 1

confirm that my initial conditions are correct : dx/dt = x^2, dx/dt = -xy and du/dt = u^2. Initial conditions are that u = 1 on x=y^2. from all this, dy/(-xy) = dt => y(t) = c_2 e^(-t x) => that y(0,s) = c_2=s. Since x=y^2 then x(0,s) = s^2

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