Consider a 2-digit message using replication as its data correcting codes, e.g., 01|01 (the last two digits are just the replication of the message). Now, a receiver obtains a raw message as "0100". By the algorithm, it automatically read it as 00. On the other hand, a message using double replication (e.g., 01|01|01) is also sent. Its corresponding receiver gets "010001” and read it as 01. Which receiver has higher chance to restore the original message correctly? Why? (you do not need to elaborate the exact probability in your explanation)

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The solution of this problem is as below The second receiver ... View the full answer