Consider a beam of mixed some unknown ions ) of the same nature ) and protons. After collimations ( that is the rays of the beam are made parallel) charged are accelerated from rest through a potential difference V = 10^4V at this point, they enter a space with a uniform field B = 0.1 T in direction perpendicular to B. due to the field they change direction of motion. We observe that when they have been deviated by 180 degrees with respect to the initial direction, the charges form 2 beams at distance d=12cm with respect to each other. We know that the proton beam runs along a circle with smaller radius with respect to the ion beam and we know that the e/m for the proton beam is equal to e/m =9.7x 10^7 C/kg. gor simplicity suppose the charges move on the plane of your screen and field is in the direction penetrating the screen. you need to calculate the q/mi for the ion beam ( q is the ion charge)

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To calculate the chargetomass ratio qmi for the ion beam we can use the principles of charged partic... View the full answer