Consider a Boolean Algebra $,x.y+x^{\text{'}}.z+yz=x.y+x^{\text{'}}.z,(a+b{)}^{\text{'}}(a^{\text{'}}+b{)}^{\text{'}}=0F=ab+b(\frac{?}{\text{b}\text{a}\text{r}}(ad)+\frac{a}{b}ar(c))AND,OR(w\frac{+}{b}ar(y)z)(x\frac{+}{b}ar(w)z)F=abc+a^{\text{'}}bc+a^{\text{'}}{b}^{\text{'}}c+ab{c}^{\text{'}}+a^{\text{'}}{b}^{\text{'}}{c}^{\text{'}}F=y(w{z}^{\text{'}}+wz)+xyF(x,y,z)=(x+y^{\text{'}}+z)(x+z^{\text{'}})+yz,x,yzF\frac{?}{b}=ar(xy)(wz\frac{+}{b}ar\frac{w}{b}ar(z))(w\frac{+}{b}ar(xz)),w,x,$yzA,$BC{F}_1{F}_2(1)$

$a$