Consider a cannon 10 meters above the ground and horizontal or parallel to the ground that fires
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Question:
Consider a cannon 10 meters above the ground and horizontal or parallel to the ground that fires cannonballs out over a field. Parallel to the ground means that the angle of the firing is at 0o with respect to the ground as shown in the drawing.
Part A Calculations:
For each of the initial velocities in Table 1 Part A below,
- determine how long the ball is in the air. Show an example calculation here for the initial velocity of 5m/s and place your answer in column 2.
- Find how far the ball goes. Show an example calculation here for the initial velocity of 5m/s and place your answer in column 4.
Part B Calculations:
Now consider the cannon at an angle of 30o instead of 0o.
For each of the initial velocities in Table 1 Part B below,
- determine how long the ball is in the air and put your answer in the table. In order to determine the time in the air, you will need to solve a quadratic equation for the time t. A rather quick way to do this is to use a quadratic equation solver like that found at https://www.mathsisfun.com/quadratic-equation-solver.html. Show example work/calculations (you should show here how you obtained the quadratic equation you use in the solver) for the initial velocity of 5m/s and place your answer in column 2.
- Find how far the ball goes and put your answer in the table. Show example work/calculations here for the initial velocity of 5m/s and place your answer in column 4.
Table 1
PART A - Height 10m, Angle 0o | |||||
Initial velocity in m/s | Time in the air (secs) | Measured time in the air (secs) | Range or distance (m) | Measured range or distance (m) | Measured range using tape measure (m) |
5 | |||||
10 | |||||
15 | |||||
PART B - Height 10m, Angle 30o | |||||
5 | |||||
10 | |||||
15 | |
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