Question: Consider a CPU with a byte-addressable main memory of 216 bytes and a block size of 4 bytes. Assume that a direct mapped cache consisting

Consider a CPU with a byte-addressable main memory of 216 bytes

Consider a CPU with a byte-addressable main memory of 216 bytes and a block size of 4 bytes. Assume that a direct mapped cache consisting of 64 lines is used with this CPU. (0) How is a 16-bit memory address divided into byte number, line number, and tag? (ii) Into what line would bytes with each of the following addresses be stored? 0000 0001 0011 0011 1101 0010 1000 1000 1011 1010 0100 0101 0010 1010 0001 0000 (iii) Suppose the byte with address 0100 0010 0001 0001 is stored in the cache. What are the addresses of the other bytes stored along with it? (iv) How many bytes of memory in total can be stored in the cache

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