Consider a double effect forward feed Evaporator as displayed in the figure below. The saruration pressure of the steam being fed into evaporator 1 is 100Kpa and the . Sre pelowing the saturation 2 The concentrate of the feed and the liquid leaving evaporator 2 is 10% and 50%, respectively. Feed temperature is 30C. Assume: 1. The heat capacity of the liquid solution is 4KJ/kg.K ( constant) 2. The BPRC=x2+2x+3 ( where x is solution concentration in fraction) 3. U1, U2 are 1000,2000W/m2K, respectively. 4. H1=H2+2(BPR1) and H2=H0+2(BPR1) H1,H2,H4,H2 are Enthalpies and Saturation Enthalpies of streams l and 2 , respectively. 5. V1=2V2 and arcas of evaporator 1 and 2 , are equal. 6. The heat transfer of the process is at steady state conditions. 7. Feed rate entering the Evaporator is 20000kg per hr. 8. Rate of heat transfer in evapotator 1 and 2 are equal. 9. No entraiment of Solids in vapor Calculate: L1,L2,V1,V2 and total Steam Rate S ( all in kg/hr ) required