Consider a double effect forward feed Evaporator as displayed in the figure pelow. The saturation pressure of the steam being fed into evaporator 1 is 100Kpa and the figure pelow. The saturation Saving the evaporator 2 is 10% and 50% The concentrate of the feed and the liquid leaving evaporator 2 Assume: 1. The heat capacity of the liquid solution is 4KJ/Kg.K ( constant) 2. The BPRC=x2+2x+3 ( where x is solution concentration in fraction) 3. U1, U2 are 1000,2000W/m2K, respectively. 4. H1=H22+2(BPR1) and H2=H3+2(BPR1) H1,H2,H1,H2 are Enthalpies and Saturation Enthalpies of streams l and 2 , respectively. 5. V1=2V2 and areas of evaporator 1 and 2 , are equal. 6. The heat transfer of the process is at steady state conditions. 7. Feed rate entering the Evaporator is 20000kg per hr. 8. Rate of heat transfer in evapotator 1 and 2 are equal. 9. Wo entraiment of Solids in vaper Calculate: L1,L2,V1,V2 and total Stcam Rate S ( all in kg/hr ) required