Consider a five$-$sided closed polygon traverse.

$A=132{47}^{\text{'}}{06}^{\text{'}\text{'}},B=108{46}^{\text{'}}{18}^{\text{'}\text{'}}$

$C=107{19}^{\text{'}}{37}^{\text{'}\text{'}},D=81{50}^{\text{'}}{36}^{\text{'}\text{'}}$

$E=109{16}^{\text{'}}{18}^{\text{'}\text{'}}.($Note: line $BC$ bears SE$.)$ The

lengths of the sides $($in feet$)$ are as follows:

$AB=202\mathrm{.}74,BC=283\mathrm{.}87,CD=498\mathrm{.}37,$

$DE=320\mathrm{.}33,$ and $EA=380\mathrm{.}78.$ The

coordinates of station A are $x=20,000\mathrm{.}00ft$

and $Y=15,000\mathrm{.}00ft$

Part A

Compute the area enclosed by the traverse above using DMDs$.$

Express your answer in feet squared to five significant figures. Note: Traverse does not need to be

adjusted to determine the correct answer.