Consider a hypothetical 32-bit microprocessor having 32-bit instructions composed of two fields. The first byte contains the opcode, and the remainder an immediate operand or an operand address.

1. What is the maximum directly addressable memory capacity (in bytes)?

To my understanding, the answer would be 2^24 bits, since the first 8 bits are used by the opcode. I looked this question up and almost every answer says 2^24 bytes, not bits, which would be about 16MB. Why is it 2^24 bytes and not 2^24 bits?