Question: Consider a new cipher block chaining (NCBC) scheme where mn+1 cn mn is encrypted to yield Cn+1 (recall that in the regular CBC, mn+1
Consider a new cipher block chaining (NCBC) scheme where mn+1 cn mn is encrypted to yield Cn+1 (recall that in the regular CBC, mn+1 cn is encrypted to yield Cn+1). (a) With regular CBC, if one ciphertext block is lost, how many plaintext blocks are lost? (b) With NCBC, why do things get back in sync if cn and C+1 are switched? (c) How about if a ciphertext block is lost? (d) How about if ciphertext block n is switched with ciphertext block n+2? (e) How about any permutation of the first n blocks?
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a With regular CBC if one ciphertext block is lost only the corresponding plaintext block is lost In ... View full answer
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