Consider a one way function f and the sequence f(x1)f n (x2), f 2 (x1)f n1 (x2), , f n (x1) f(x2), where f n is simply f applied n times Given one element of the sequence, could you compute another

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Question: Consider a one way function f and the sequence f(x1)f n (x2), f 2 (x1)f n1 (x2), . . . , f n (x1) f(x2),

Consider a one way function f and the sequence f(x1)f ⁿ (x2), f ²(x1)f ⁿ¹(x2), . . . , fⁿ (x1) f(x2), where fⁿ is simply f applied n times. Given one element of the sequence, could you compute another?

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