Consider a parallel$-$plate capacitor where the upper plate is held stationary while the lower plate is free to move. The surface area of each plate is $\backslash (20\backslash$mathrm$\{$~cm$\}^\{2\}\backslash )$ and there is a $5$ mm air$-$gap between the plates. Determine the electric force acting on the bottom plate as well as the energy stored in the electric field. Assume the potential difference between the two plates is $10$ kV and the permittivity of free space is $\backslash (10^\{-9\}/36\backslash$pi $\backslash$mathrm$\{$~F$\}/\backslash$mathrm$\{$m$\}\backslash ).$