Consider a particle of mass m $=1\mathrm{.}0$ kg attached to a spring of spring constant k $=5\mathrm{.}0$times $104$ N$/$m$.$ The potential energy of the spring is given as U$($x$)=$ kx$2/2.$ The mass is initially at x $=1$ cm$,$ with initial velocity v$0=2\mathrm{.}0$ m$/$s$.$

What is the furthest point$($s$)$ the mass can reach during its subsequent motion $?$

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To find the furthest points the mass can reach during its subsequent motion we need to ana... View the full answer