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Consider a simple 8-bit configuration register, where each bit sets the configuration of 8 different pins ([7...0]), where setting a bit to 0 means configuring

Consider a simple 8-bit configuration register, where each bit sets the configuration of 8 different pins ([7...0]), where setting a bit to 0 means configuring input and setting 1 means output: char *ioDirConfigRegister = 0x20000000; // Location of configuration register in memory mapped IO If we want to set the 4th (0 indexed) pin to output, why is the following wrong? *ioDirConfigRegister = 1 << 4; Choice 1 of 5:We cannot use the shift operations here. We should use *ioDirConfigRegister = 0

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The code ioDirConfigRegister 1 4 is used to set the 4th pin 0indexed to output but it is incorrect for the following reason The code ioDirConfigRegist... blur-text-image
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