Question: Consider a two - block system moving in the gravity field shown in Fig. 3 . Figure 3 : A two - block system with

Consider a two-block system moving in the gravity field shown in Fig. 3.Figure 3: A two-block system with a lin-
ear spring and a rigid rod
The two blocks have the same mass m and are connected via a rigid, massless rod of length l.
As a result of the gravitational acceleration g, block 1 moves horizontally and block 2 can only
move vertically. There is no friction in this system. Moreover, block 1 is connected to a wall
via a linear spring that has a spring constant k and a negligible free length. Therefore, the
elongation of the spring is the position x of block 1 from the wall. For block 2, its horizontal
distance to the wall is l and its vertical position is y as shown in Fig. 3. Use Newtonian
mechanics to answer the following questions.
(a) Draw a free-body diagram of the two blocks.
(b) Apply Newton's second law to derive the equations of motion of the two blocks. Elimi-
nate constraint force(s) from your equations of motion to obtain a nonlinear, differential
equation governing only the variable (t), where is the angle between the rigid rod and
the vertical as shown in Fig. 3.
(c) Determine an algebraic equation governing equilibrium positions 0 of the system. The
equation should involve parameters such as mg and kl . Show that there is only one
possible equilibrium for 002.
(d) Derive a linearized equation of motion around the equilibrium position. If the two-block
system is subjected to disturbance, will the system oscillate around the equilibrium
position? Why?
Consider a two - block system moving in the

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