Question: Consider an experiment that has two possible outcomes (like the toss of a coin). The outcomes are labelled as 01 and 02 . The probabilities

Consider an experiment that has two possible outcomes (like the toss of a coin). The outcomes are labelled as 01 and 02 . The probabilities (P1 and P2) of each outcome is 1/2. Before conducting the experiment we are uncertain to some degree about the result. Now consider a second (different) experiment that also has two possible outcomes. In this case, the outcomes are labelled as 01' and 02' . The probabilities ( Pl, and P; ) of each outcome are now 1/5 and 4/5 respectively. Intuitively, we would might use the word \"uncertainty\" to say that the outcome of the first experiment is more uncertain than that of the second. In a third experiment with four outcomes P1 = P2 = P3 = P4 =% and a fourth experiment with six outcomesP1 = P2 = P3 = P4 = P5 = P6 = we might again say that the outcome of the fourth experiment is more uncertain than that of the third experiment. In a sense, uncertainty is a measure ofthe degree to which we are able to correctly guess at the outcome of an experiment. It would be great to make this measure quantitative. We will dojust such a thing and will arrive at the expression: S ='ZPi Inf}. Compute the uncertainty for the case whereP1 = P2 = % and for the case where Pl, 2 % and f P2 = g. How do the uncertainties compare? Compute the uncertainty for the case whereP1 = P2 = P3 = P4 = %and for P1 = P2 = P3 = P4 = P5 = 136 2 %.Again, compare the uncertainties
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