Question: Consider inserting the keys 2 1 , 2 2 , 3 1 , 4 , 1 5 , 2 8 , 1 7 , 3

Consider inserting the keys 21,22,31,4,15,28,17,35,59 into a hash table of length m=11 using open
addressing with the auxiliary hash function hat(h)(k)=k. Illustrate the result of inserting these keys using linear
probing, using quadratic probing with c1=1, and c2=3, and using double hashing with h1(k)=k and h2(k)=
1+(kmod(m-1)), respectively.
Consider inserting the keys 21,22,31,4,15,28,17,35,59 into a hash table of length

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