Consider that a relation $R$ has $5$ tuples and $4$ attributes. And the

relation $S$ has $6$ tuples and $5$ attributes. The result of the query

$(RS)$ will produce:

a$.$ none of these

b$.$ a new virtual table with $9$ attributes but the number of tuples is decided based on the join condition

c$.$ a new virtual table with $9$ tuples and $30$ attributes

d$.$ a new virtual table with $30$ tuples and $9$ attributes