Consider the area between the graphs x + 4y = 26 and r + 6 = y?. This area can be computed in two different ways using integrals %3D First of all it can be computed as a sum of two integrals f f(x)dx + g(x)dx where a = , b = , c = and f(x) = g(x) = %3! h(y)dy where a = , B and h(y) = Alternatively this area can be computed as a single integral Either way we find that the area is.