Question: Consider the curve x = t3 - 27t + 1, and y = t3 - 6t2 - 4. (a) (3 points) Find the points on

Consider the curve x = t3 - 27t + 1, and y = t3 - 6t2 - 4. (a) (3 points) Find the points on the curve (x, y) where the line tangent to the curve is horizontal. (b) (3 points) Find the points on the curve (x, y) where the line tangent to the curve is vertical. (c) (3 points) Find any values of t where the slope of the tangent line to the curve is 1

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