Question: Consider the differential equation. x y2 dy 3 3 =x + y , y ( 3 ) =1 dx (a) Solve the initial value problem.

Consider the differential equation. x y2 dy 3 3 =x + y , y ( 3 ) =1 dx (a) Solve the initial value problem. The solution is y ( x ) = (b) Determine at least approximately where the solution is valid. (Round your answer to two decimal places.) The solution is valid in the interval x <

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