Question: Consider the equation 2 sin x + 3 x - 7 = 0 a). Use Rolle's theorem to show that the equation has at most

Consider the equation 2 sin x + 3 x - 7 = 0

a). Use Rolle's theorem to show that the equation has at most one root

b). Use Newton's method starting with the initial approximation x₁ = 4, to find x₂, the second approximation to the solution of the equation 2sinx + 3x -7 = 0

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