Question: Consider the following algorithm, Algorithm S ( n ) { if ( n = 1 ) { } else { X 0 : S (

Consider the following algorithm,
Algorithm S(n)
{ if(n =1){} else { X 0: S(n -1) Y(n)}
Let the time complexities of XI) and Y(n) are O(1) and O(1/ n) Derive the recurrence relation for the algorithm Sin) and its time complexity.
Which of the following option is correct?
T(n)=constant, if n =1=1+ T(n -1), if n >1 and O(log(n)) respectively
T(n)=constant. if n =1=1+ T(n -1)+ T(1/n),if n>1 and theta(log(n)) respectively
T(n)=constanut. if n =1=1+ T(n -1)+1/n , if n >1 and theta(n) respectively
T(n)=constant, if n =1=1+ T(n -1),if n>1 and Omega(n) respectively

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