Question: Consider the following algorithm for determining for non - negative . def pow ( x , n ) : result = 1 do n times:

Consider the following algorithm for determining
for non-negative
.
def pow(x, n):
result =1
do n times:
result *= x
return result
Provide pseudocode for a recursive implementation of the above algorithm.
How many multiplications does this algorithm perform? Justify your answer.
Provide pseudocode for a recursive algorithm that computes
with
multiplications.
Provide pseudocode for an iterative version of the
algorithm.

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