Question: Consider the following algorithm(in java) Algorithm foo(n) if n = 0 then return 1 else { x 0 for i 1 to n do x
Consider the following algorithm(in java)
Algorithm
foo(n)
if n = 0 then return 1
else { x 0
for i 1 to n do x x + x/i
x x + foo(n 1)
return x }
The time complexity of this algorithm is given by the following recurrence equation:
f(0) = c1
f(n) = f(n 1) + c2n + c3, for n > 0
where c1, c2, and c3 are constants. Solve the recurrence equation and give the value of f(n) and its order using big-Oh notation. You must explain how you solved the recurrence equation
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