Question: Consider the following ARM assembly code: For the given ARM code, why register 1 1 is not pushed in the routine function 1 ( in

Consider the following ARM assembly code:
For the given ARM code, why register 11 is not pushed in the routine function1( in the first statement)?
11 is pushed
pushing {r4-r10} is enough
r11 is not used as the local variable
Consider the following ARM assembly code: For the given ARM code,

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