Consider the following bucket sort algorithm, the pseudocode is given below: Special BucketSort(arr): n = arr.length arrBucket[0..n-1] be an...

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Consider the following bucket sort algorithm, the pseudocode is given below: Special BucketSort(arr): n = arr.length arrBucket[0..n-1] be an empty array of lists for i= 0 to n-1 //hash function determines which bucket the element goes into insert arr[i] into list arrBucket[hash(arr[i])] for i=0 to n-1 sort list arrBucket[i] using insertion sort concatenate the lists arrBucket[0], arrBucket[1], ..., arrBucket[n-1] together in order a) What is the worst-case and best-case running time of this sorting algorithm and provide the scenarios in which each of these happen. [5 pts] b) By replacing insertion sort with a more efficient merge sort or heap sort in line 9 of the pseudocode, bucket sort can achieve a worst-case running time of O(nlogn) instead of 0(n²). Argue why switching insertion sort to a more "efficient" sort is not a good idea. [5pts] c) If you have to sort a huge list that can't fit into memory. Would you use bucket sort or quick sort? Why?[5pts] Activate Win Go to Settings to

Answer rating: 100% (QA)

a Worst case and Best case Run Time Best case The best case scenario for bucket sort occurs when all elements in the input array are uniformly distrib View the full answer