Question: Consider the following code. half | = let h [] rl = 1 == r h(r) |=1== h(s) (x:xs) I = hs xs (x:1)

Consider the following code. half | = let h [] rl = 

Consider the following code. half | = let h [] rl = 1 == r h(r) |=1== h(s) (x:xs) I = hs xs (x:1) in hilo What does half I compute? Show your reasoning.

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