Question: Consider the following discrete - time LTI system x [ k + 1 ] = A x [ k ] y [ k ] =

Consider the following discrete-time LTI system
x[k+1]=Ax[k]
y[k]=Cx[k]
where
A=[0201]
and
C=[c1c2]
Argue that no matter what value you will choose for c1 and c2 the system is always unobservable.
Consider the following discrete - time LTI system

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