Question: Consider the following Erlang function: mystery( 1 ) -> 1; mystery( 2 ) -> 4; mystery( N ) when N >= 0 -> mystery( N

Consider the following Erlang function:

mystery( 1 ) -> 1;

mystery( 2 ) -> 4;

mystery( N ) when N >= 0 ->

mystery( N 1 ) + ( 2 * mystery( N div 2 ) ) + N.

What would be returned by the following function calls? If a function call would crash, go into an infinite loop, or otherwise cause an error, write error.

mystery( 0 ) =

mystery( 1 ) =

mystery( 3 ) =

mystery( 4 )

mystery( 5 )

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