Consider the following function and closed interval. f(x) = 5x3, [1, 2] Is f continuous on the closed interval [1, 2]? Yes No If f is differentiable on the open interval (1, 2), find f'(x). (If it is not differentiable on the open interval, enter DNE.) f' ( x ) = 15x2 Find f(1 ) and f ( 2 ) . f(1) = 5 f(2) = 40 Find f(b) - f(a) for [a, b] = [1, 2]. b - a f ( b ) - f (a ) - 35 b - a Determine whether the Mean Value Theorem can be applied to f on the closed interval [a, b]. (Select all that apply.) Yes, the Mean Value Theorem can be applied. No, because f is not continuous on the closed interval [a, b]. No, because f is not differentiable in the open interval (a, b). None of the above. If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that f'(c) = )). If the Mean Value Theorem cannot be applied, explain why not. (Enter your b - a answers as a comma-separated list. If the Mean Value Theorem cannot be applied, enter NA.) C = 1.527 X