Question: Consider the following host routing table: C:>route print |================= Interface List 0x1 0x30004 ...00 e0 29 44 12 65 Active Routes: ===== ====== MS




Consider the following host routing table: C:\>route print |================= Interface List 0x1 0x30004 ...00 e0 29 44 12 65 Active Routes: ===== ====== MS TCP Loopback interface SMC EtherPower II 10/100 Ethernet Adapter ===== ===== Network Destination Netnask Gateway Interface Metric 0.0.0.0 0.0.0.0 192.168.15.254 192.168.15.1 20 127.0.0.0 255.0.0.0 127.0.0.1 127.0.0.1 1 192.168.15.0 255.255.255.0 192.168.15.1 192.168.15.1 20 192.168.15.1 255.255.255.255 127.0.0.1 127.0.0.1 20 192.168.15.255 255.255.255.255 192.168.15.1 192.168.15.1 20 224.0.0.0 255.255.255.255 240.0.0.0 255.255.255.255 192.168.15.1 192.168.15.1 192.168.15.1 192.168.15.1 20 1 Default Gateway: 192.168.15.254 ============= == Persistent Routes: None What does it mean when the gateway IP is the same as the Interface IP? the packet being sent will go through the default gateway. the local host is the default gateway. the packet being sent will be sent to the local network. What type of address is 169.254.120.1? a) Network Address b) Multicast address d) Loopback Address e) APIPA Given the following topology with all SATs fully populated what is the SAT entry in Switch B for Host C? port 7 port 1 Sith A port 2- port 4 port 3 Host A Host B Host C 000 Scanner Printer port 2- port 3- port 1- port 6- Switch B port 4 port 5 PDA Smart Phone Projector Screen -port 2 port 1 Copier port 3- Swito C port 5 port 4 Tablet Device PC PDA
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