Question: Consider the following initial value problem: ( t 2 1 4 t + 4 0 ) dydt = ywithy ( 7 ) = 1 .

Consider the following initial value problem:(t214t+40)dydt=ywithy(7)=1.
Solve the initial value problem (find y as a function of t.)
y=
On what interval is the solution valid?
It is valid for

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