Question: Consider the following language: ULONGER - CYCLE = { G , k | G is a graph, k an integer, and G has a simple

Consider the following language:
ULONGER-CYCLE ={G, k| G is a graph, k an integer, and G has a simple cycle of length > k}.
Question 21(1 point)
To show that ULONGER-CYCLE is NP-hard, it suffices to show that
X is polynomially many-one reducible to ULONGER-CYCLE for some NP-complete X.
Question 21 options:
True
False
Question 22(1 point)
To show that ULONGER-CYCLE is NP-hard, it suffices to show that
ULONGER-CYCLE is polynomially many-one reducible to X for some NP-complete X.
Question 22 options:
True
False
Question 23(2 points)
Consider the following list of NP-complete languages. Select the language that would be most helpful in proving that ULONGER-CYCLE is NP-hard.
Recall that:
A clique C in a graph is a subset of the vertices such that every
two vertices in C are adjacent.
A Hamiltonian cycle in a graph G is a cycle that goes through each
vertex exactly once.
An independent set I in a graph is a subset of the vertices such
that no two vertices in I are adjacent.
Question 23 options:
CLIQUE ={G, k| G is a graph, k is an integer, and G has a clique of size k}.
INDEPENDENT-SET ={G, k| G is a graph, k is an integer, and G has an independent set of size k}.
SAT ={\phi |\phi is a satisfiable boolean formula}
UHAMCYCLE ={G| G is a graph with a Hamiltonian cycle }.
Question 24(4 points)
Describe a reduction that shows that ULONGER-CYCLE is NP-hard. You must reduce to or from the language selected in the last question. (You do not have to show that your reduction is correct.)
Question 24 options:
Question 25(2 points)
Is ULONGER-CYCLE NP-complete? Briefly explain your answer.

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Programming Questions!