Question: Consider the following linear programming problem: Maximize Z=Z=600xx + 500yy (profit in $) subject to 3x+2y183x+2y18 x+2y10x+2y10 y4y4 x , y0x , y0 Identify the
Consider the following linear programming problem: Maximize Z=Z=600xx + 500yy (profit in $) subject to 3x+2y183x+2y18
x+2y10x+2y10
y4y4
x , y0x , y0
- Identify the optimal solution. How much is the maximum profit?
- x=0,y=5x=0,y=5 is the optimal solution, and the maximum profit is $2500
- x=2,y=4x=2,y=4 is the optimal solution, and the maximum profit is $3200
- x=4,y=3x=4,y=3 is the optimal solution, and the maximum profit is $3900
- x=6,y=0x=6,y=0 is the optimal solution, and the maximum profit is $3600
- x=0,y=4x=0,y=4 is the optimal solution, and the maximum profit is $2000
- x=10,y=0x=10,y=0 is the optimal solution, and the maximum profit is $6000


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