Consider the following linear programming problem: Maximize Z = 1500x+3100y(profit in$) Subject to 3x+2y19 x+2y=10y4 x,y20 B) Identify the optimal solution. How much is the maximum profit? x = 4, y = 3 x = 4, y = 3 is the optimal solution, and the maximum profit is $15300 x = 2, y = 4x = 2, y = 4 is the optimal solution, and the maximum profit is $15400 x = 0, y = 5 x = 0, y = 5 is the optimal solution, and the maximum profit is $15500 x = 0, y = 4 x = 0, y = 4 is the optimal solution, and the maximum profit is $12400 x = 6, y = 0x = 6, y = 0 is the optimal solution, and the maximum profit is $9000 x = 10, y = 0 x = 10, y = O is the optimal solution, and the maximum profit is $15000