Question: Consider the following MIPS loop: LOOP: slt $t2, $0, $t1 beq $12, $0, DONE subi $t1, $t1, 1 addi $s2, $s2, 2 j LOOP
Consider the following MIPS loop: LOOP: slt $t2, $0, $t1 beq $12, $0, DONE subi $t1, $t1, 1 addi $s2, $s2, 2 j LOOP DONE: Assume that the register $t1 is initialized to the value 10. What is the value in register $s2 assuming $s2 is initially zero?
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This MIPS loop decrements the value in register t1 by 1 in each iteration ... View full answer
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