Question: Consider the following program. public class Test {public static void foo(String text) {try {Stem.out.println(text.substring(0, text.indexOf(' ')));} catch(IndexOutOfBoundsException e) {System.out.println(text); return;} foo(text.substring(text.indexOf(' ')+1));} public static void

 Consider the following program. public class Test {public static void foo(String

Consider the following program. public class Test {public static void foo(String text) {try {Stem.out.println(text.substring(0, text.indexOf(' ')));} catch(IndexOutOfBoundsException e) {System.out.println(text); return;} foo(text.substring(text.indexOf(' ')+1));} public static void main (String[] args) {foo("one two three");}} Which lines are the base case, work step, and recursive step respectively? What will the program print out? What will print out if you move the recursive call before the try? One of these is called head recursion, one is called tail recursion. Which is which and why? How many times will the foo method recurse with the given string? How many times will it recurse in general? What part of the string determines the number of recursions? Express the complexity of the recursive method in big-o notation. What does N represent? Any recursive method can be rewritten using iteration and a stack. Rewrite an iterative version of this program

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